Math Mapgenerated 2026-10-25 · a354234
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P-022probeOpen2026-09-20geometry-topology

Are the topological-existence and constructive-arithmetic halves one phenomenon or two tools?

necklace · borsuk-ulam · greedy · speculative · mining-6

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Explicitly speculative. Nothing in the source chat tests this. Filed so the question stops being re-asked from scratch, not because there is evidence either way.

The statement. One body of work reaches its results by topological existence — a Borsuk–Ulam-type argument that a fair split exists, non-constructive, indifferent to arithmetic. Another reaches results about the same objects by constructive arithmetic — an explicit greedy construction with a deficit invariant and an exactness theorem at a checkpoint. They produce compatible statements about the same objects.

The friction. Compatible statements from disjoint methods admit two readings, and nothing currently distinguishes them:

  1. One phenomenon. The discrete invariant the constructive half tracks is derivable from the continuum/Borsuk–Ulam side — the constructive proof is the topological one, discretised, and the deficit invariant is a shadow of the continuum statement.
  2. Two tools. They are genuinely disjoint instruments that happen to solve related problems. The agreement is agreement about the objects, not evidence of a shared mechanism.

Why it is open rather than answered. The obvious bridge was tried and died. The hypothesis that k-thief difficulty tracks the availability of free ℤ/k actions on spheres — which would have tied the two halves together through the division-algebra ladder — does not survive PPA-completeness at k = 2 (disagreements.js, Free ℤ/k group actions are not the source of k-thief necklace difficulty). That refutation removed one candidate bridge; it did not answer the question, and the changed: field of that entry says so explicitly. This probe is that sentence, given a home.

What would settle it. Derive the deficit invariant, or its checkpoint-exactness, from a continuum statement — that is branch 1. Or exhibit a problem where the two halves give incompatible answers, or where one applies and the other provably cannot — branch 2.

What would not settle it. More instances of agreement. Agreement is what both branches predict, which is exactly why this has stayed open.

45 source lines, no addenda.

generated 2026-10-25the lab index